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order poker hands

29 May 2010 General

order poker hands
The problem revolves around the probability of poker hands?

The problem revolves around the probability of poker hands? A poker hand consists of five cards selected at random from a deck of 52 cards, where the order of choice does not matter. 1) What is a shock probavillity? (Percentage?) 2) What is the probability that a four of a kind? 3) What is the probability that a trio? (Please, someone can help me understand these problems? as I have no idea how to do them?)

1) ras 0.2% 2) bob 0.024% 3) 2.113% Explanation 1) 1 * (12/51) * (11/50) * (10/49) * (9 / 48) 2) C (5,4) 1 * (3 / 51) * (2 / 50) * (1 / 49) * (48/48) = 5 * 1 * … = 0.00024 = 0.024% 3) C (5.3) * 1 * (3 / 51) * (2 / 50) * (48/49) * (44/48) = 0.02113 = 2.113% (C (5,3) = 5 '/ 3! 2! = 10) n! * N = (-1) * n (n-2 )*…* 3 * 2 * 1 (factorial) to 5! = 5 * 4 * 3 * 2 * 1 Explanation = 120. If you put the combination obtained compared to his hand and then the first probability 1 card does not matter, for the first card. Then you have to say that the second card is the same suit in a color or range of (4.3) in its class. To wash, there are 12 letters to the left of the same suit. For (03/04) of the three types of cards of equal rank. Continue …. After that is multiplied by the combinations of possible locations combinations of poker hands. For example, bob. The 5th letter outside the car can be the first, second, … Five possible combinations here. In three of a class C (5,3) = 5 * 4 / 2 = 10 possible placements of the two cards that do not belong to the three of a kind. Multiplying all odds gives the result. Good luck! If you have more questions about probability calculations, you can always send me an e-mail to probability calculations hv284394@scarlet.be I love and will gladly help to understand more about them!

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